Question

the speed of a car is reduced from 60 km per hour to 30 km per hour over a displacement of 20 m.what is the accleration of car adssuming it to be constant?​

Answer 1

given

u=60km/hr , v=30km/hr and s=20m.20/1000=0.02km

According to Newton's third equation of motion.

v*v-u*u=2as

30*30-60*60=2*a*0.02

900-3600=0.04*a

-2700=0.04*a

-2700/0.04=a

-67500=a

or a=-67500.