Question

The speed of a car is reduced from 90 km/h to 36 km/h in 5 s.

What is the distance travelled by the car in this time interval ?​

Answer 1

Answer:87.5m

Explanation:

inital spd = 90km/hr = 25m/s

final spd = 36km/hr = 10m/s

time = 5sec

v=u+at

10=25+a×5

a=-3m/s^2

Now

x=ut +1/2at^2

x=25×5+1/2(-3)×25

x=87.5m

Answer 2

Answer:

Explanation:V=90km/h =25m/s

U=36km/h= 10m/s time=5s

acceleration =v-u/t

=25-10/5

=3m/s sq.

S=ut+1/2*at*t

S=10*5+1/2*3*5*5

S=50+1/2*75

S=50+75/2

S=(100+75)/2

S=175/2

S=87.5m ans.