Math, asked by ananyashibi24092008, 2 months ago

The speed of a car was increased from 40km/hr to 60km/hr within 5 minutes. Find its acceleration. Hint: (v=u+at).
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Answers

Answered by srijankhan8a
1

Answer:

1/54 m/s²

Step-by-step explanation:

u=40km per hour

40×5/18

u= 100/9 m/s

b=60 km

60×5/18

50/3 m/s

t= 5 min

5×60 second =300s

v= u+80

50/3 = 100/9 + a × 300

300a = 50 / 3 - 100/9

300a=150-100

_______

9

300a=50/9

a=50/9*1/300

a=1/54m/s²

Answered by ImperialGladiator
3

Answer :

240km/hr

Explanation :

Speed of the car increased from 40km/hr to 60km/hr within 5 min. Find it's acceleration.

By the acceleration formula :

 \longrightarrow \sf \:  \dfrac{(v - u)}{t}

Where,

  • v(final velocity) = 60km/hr
  • u(initial velocity) = 40km/hr
  • t(time) = 5 min or, 5/60km.

By the given values,

\sf \longrightarrow \:  \dfrac{(60 - 40)}{ \frac{5}{60} }  \\

\sf \longrightarrow \:  \dfrac{20}{ \frac{5}{60} }  \\

\sf \longrightarrow \: 20  \times  \frac{60}{5}  \\

\sf \longrightarrow \: 4 \times 60 \\

\sf \longrightarrow \: 240km/hr^2

Required answer : 240km/hr²

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