Question

The speed of a car weighing 1500 kg increases from 36 km/h to 72 km/h uniformly. What will be the change in momentum of the car?

(1 Point)

15000 kg km/h

15000 kg m/s

54000 kg m/s

54000 g m/s


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Answer 1

Answer:

Explanation:Initial velocity = 36 km/h = 36 ×  = 10m/s

Final velocity = 72 km/h = 72 ×  = 20m/s

So the change in momentum is given by,

Substituting the given values,

➝ 1500 × 20 - 1500 × 10

➝ 30000 - 15000

➝  15000

Answer 2

ANSWER :

The change in momentum of the car is 15000 Kg m/s.

GIVEN :

• Weight of the car = 1500 kg.
• Initial velocity , u = 36 km/hr.
• Final velocity , v = 72 km/hr.

TO FIND :

• Change in the momentum = ?

SOLUTION :

$\sf u \: = \: 36 \: km/hr$

$\sf u \: = \: 36 \: times \: \dfrac {5}{18}$

$\sf u \: = \: 10 \: m/s.$

$\therefore {\boxed{\sf u \: = \: 10 \: m/s}}$

Now,

$\sf v \: = \: 72 \: \times \: \dfrac {5}{18}$

$\sf v \: = \: 20 \: m/s.$

$\therefore {\boxed{\sf v \: = \: 20 \: m/s}}$

We know that,

Change in momentum, P = mv - mu.

$\implies 1500 \: \times \: 20 \: - \: 1500 \: \times 10$

$\implies 30000 \: - \: 15000$

$\therefore {\boxed{\sf P \: = \: 15000 \: kg \: m/s}}$

•°• Change in momentum will be 15000 kg m/s.