The speed of a moving body is halved.what change takes place in its kinetic energy
Answers
Answered by
0
kinetic energy is 1/4 the initial one
Answered by
4
Here is your answer
Let the mass of body be m and its initial velocity be v
so, KE= (1/2)mv^2
when velocity is halved
v'= v/2
so, KE'= (1/2)mv'^2
=(1/2)m(v/2)^2
=(1/2)mv^2/4
=KE/4
so, kinetic energy is reduced to 1/4th
Hope it is useful
Let the mass of body be m and its initial velocity be v
so, KE= (1/2)mv^2
when velocity is halved
v'= v/2
so, KE'= (1/2)mv'^2
=(1/2)m(v/2)^2
=(1/2)mv^2/4
=KE/4
so, kinetic energy is reduced to 1/4th
Hope it is useful
Similar questions