Question

the speed of a particle changes from 10ms^-1 to 30ms^-1 in 4s its acceleration is how many ms^-2​

Answer 1

Answer:

acceleration=final velocity-initial velocity/time

a=v-u/t

a=30-10/4

a=20/4

a=5m/s²

Answer 2

$\bigstar$ Given

The speed of a particle changes from 10 m/s to 30 m/s in 4 s

$\bigstar$ To Find

Its acceleration

$\bigstar$ Solution

We know that

$\red{\rm \longrightarrow a=\dfrac{v-u}{t}}$

Here

• a = acceleration
• u = initial velocity
• v = final velocity
• t = time

Units

• a = metre per second squared (m/s²)
• u = metre per second (m/s)
• v = metre per second (m/s)
• t = seconds (s)

According to the question

We are asked to find its acceleration

Therefore

We must find "a"

Given that

The speed of a particle changes from 10 m/s to 30 m/s in 4 s

Hence

• u = 10 m/s
• v = 30 m/s
• t = 4 s

Substituting the values

We get

$\purple{\rm \longrightarrow a=\dfrac{30-10}{4} \ m/s^{2}}$

$\orange{\rm \longrightarrow a=\dfrac{20}{4} \ m/s^{2}}$

Hence

$\pink{\rm \longrightarrow a=5 \ m/s^{2}}$

Therefore

$\checkmark$ Acceleration = 5 m/s²