the speed of a particle moving along a straight line becomes half after every next second the initial speed is v° the total distance travelled by the particle will be
Answers
Answer:
3V/2
Explanation:
the speed of a particle moving along a straight line becomes half after every next second the initial speed is v° the total distance travelled by the particle will be
initial speed = V
Speed after 1 sec = V/2
a = V/2 - V = -V/2
Distance covered using V² - U² = 2aS
(V/2)² - V² = 2(-V/2)S
=> - 3V²/4 = -V/S
=> S = 3V/4
Speed after 2 Sec = V/4
a from 1 to 2 sec = V/4 - (V/2) = -V/4
Distance Covered = (V/4)² - (V/2)² = 2(-V/4)S
=> V²/16 - V²/4 = -(V/2)S
=> -3V²/16 = -(V/2)S
=> S = 3V/8
In 3rd sec distance = 3V/16
Total distance = 3V/4 + 3V/8 + 3V/16 +..................................................
a = 3V/4 r = 1/2
Sum = a/(1 - r) = (3V/4)/(1 - 1/2) = (3V/4)/(1/2) = 3V/2
total distance traveled by the particle will be 3V/2
Explanation:
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