Question

the speed of a particle moving along a straight line becomes half after every next second the initial speed is v° the total distance travelled by the particle will be​

Answer 1

Answer:

3V/2

Explanation:

the speed of a particle moving along a straight line becomes half after every next second the initial speed is v° the total distance travelled by the particle will be​

initial speed = V

Speed after 1 sec = V/2

a = V/2 - V = -V/2

Distance covered  using V² - U² = 2aS

(V/2)² - V² = 2(-V/2)S

=> - 3V²/4 = -V/S

=> S = 3V/4

Speed after 2 Sec = V/4

a from 1 to 2 sec = V/4 - (V/2) = -V/4

Distance Covered = (V/4)² - (V/2)² = 2(-V/4)S

=> V²/16 - V²/4  = -(V/2)S

=> -3V²/16 = -(V/2)S

=>  S = 3V/8

In 3rd sec distance = 3V/16

Total distance = 3V/4  + 3V/8  + 3V/16  +..................................................

a = 3V/4  r = 1/2

Sum =  a/(1 - r)  =  (3V/4)/(1 - 1/2)  =  (3V/4)/(1/2)  = 3V/2

total distance traveled by the particle will be​ 3V/2

Answer 2

Explanation:

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