Question

The speed of a projectile at its Maximum Height is √3/ 2 times it's Initial Speed. If the Range of the projectile is p times the maximum height attained by it ,then p=
A) 4/3
B) 2√3
C) 4√3
D) 3/4

Answer 1

4/3

23–√

43–√

3/4

Answer :

C

Solution :

( c) Given 3–√u2=ucosθ = speed at maximum height

or cosθ=3–√2 or θ=30∘ …(i)

Given that PHmax=R…(ii)

We know Hmax=Rtanθ4

P=RHmax=4tanθ=4tan30∘=4(3–√).Answer:

Explanation:

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