the speed of a projectile at its maximum height is 6m/s the if it stays in the air for a total time of 8 sec , its horizontal range is
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Explanation:
The projectile would move with its horizontal component of velocity v0 cosθ = 6ms-1 in all its trip. The time it stays in space is 8 sec. Thus the horizontal range it would cover is 8 sec x 6ms-1 = 48 m.Aug 20, 2019
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Answer:
h=2u²sin2x/g
=2u².sinx.cosx/g
=2(usinx) (ucosx) /g
=2×40×6/10
=48m
Explanation:
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