the speed of a vehicl of mass 500 kg incres from 36km/h to 72km/h calculate the increase in its k.E
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m = 500 kg
Δv = [ 72 - 36 ] = 36 km/h ⇄ 10 m/s
Ek .......... ?
Answer
Ek = 1/2 mv²
Ek = 1/2 x 500 x 10²
Ek = 250 x 100
Ek = 25.000 Joule
Δv = [ 72 - 36 ] = 36 km/h ⇄ 10 m/s
Ek .......... ?
Answer
Ek = 1/2 mv²
Ek = 1/2 x 500 x 10²
Ek = 250 x 100
Ek = 25.000 Joule
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