Question

The speed of an ant is 2t+10 and after travelling for t minutes it covers a distance of 12 m findt

Answer 1

speed=distance÷time
2t+10=12÷t
t^2+5t-6=0
(t-1)(t+6)=0
t=1

Answer 2

The speed of an ant = (2t+10)m / min    ( given)

Time = t min                                              ( given)

Distance = 12 m                                        ( given)

∴ Speed =  Distance ÷ Time

(2t+10)m / min = $\frac{12}{t}$

⇒t ( 2t +10 = 12

⇒ 2t² + 10t - 12=0

⇒t² + 5t - 6

⇒t² + 6t - t - 6=0

⇒ t ( t +6 ) - 1 ( t + 6) =0

⇒ ( t+6) ( t -1) =0

⇒ ( t + 6 ) =0

t = -6

( t-1) = 0

t = 1

t = 1, -6

For the reason that time cannot be negative so, t = 1

∴ the value of t is 1 minute

Ans :- t = 1 minute.

#SPJ3