Question

The speed of an arrow fired from a compound bow is about 45 m/s.
(a) A Tartar archer sits astride his horse and launches an arrow into the air, elevating the bow at an angle of 10° above the horizontal. If the bow is 2.25 m above the ground, what is the arrow's range? Assume that the ground is level, and ignore air resistance.

Answer 1

Answer:

horizontal velocity = u cos 10

vertical velocity = u sin 10

u = 45m/s

time = vertical velocity/ 9.8

= 45x sin 10 / 9.8

= 0.8 sec approx

horizontal range = t x u cos 10 = 35.5 m approx

additional range due to height of horse = 2.25/ tan 10= 12.76 m

total range = 12.76+35.5= 48.26 m