The speed of an ordinary train is x km per hr
and that of an express train is (x + 25) km per hr.
(i) Find the time taken by each train to cover
300 km.
(ii) If the ordinary train takes 2 hrs more than
the express train; calculate speed of the
express train.
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that is an answer if I wrong so I am sorry
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(i) Given,
Speed of the ordinary train = x km/hr
Speed of the express train = (x + 25) km/hr
Distance = 300 km
We know that,
Time = Distance/ Speed
So, the time taken by the ordinary train to cover 300 km = 300/x hrs
And the time taken by the express train to cover 300 km = 300/ (x + 25) hrs
(ii) From the question, it’s given that the ordinary train takes 2 hours more than the express train to cover the distance of 300kms.
Hence:
7500 = 2x2 + 50x
2x2 + 50x – 7500 = 0x2 + 25x – 3750 = 0
x2 + 75x – 50x – 3750 = 0
x(x + 75) – 50(x + 75) = 0
(x – 50) (x + 75) = 0
Thus:
x = 50 or -75
As speed cannot be negative we shall ignore x = -75
Therefore:
The speed of the express train = (x + 25) km/hr = 75 km/hr
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