The speed of boat is 5kmperhour in still water it crosses a river of width 1 km along shortest possible path in 15 min the velocity of river water is
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Given - v=5km/hr
S=1km t=15/60 hr.
From second eq .
Of motion
1=1/2×a×(15/60)^2a=8m/s^2
From first eq . Of motion
5= u+8×15/60
Hence u=3km/hr
S=1km t=15/60 hr.
From second eq .
Of motion
1=1/2×a×(15/60)^2a=8m/s^2
From first eq . Of motion
5= u+8×15/60
Hence u=3km/hr
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