Science, asked by sekharcherukure7310, 11 months ago

The speed of light in water is 2.25 × 108ms-1. If the speed of light in vacuum is 3 × 108ms-1, calculate the refractive index of water. (Ans:1.33)

Answers

Answered by Richa189381
5
Given- the speed of light in water-2.25×108m/s
speed of light -3×108m/s
refractive index of water with respect to the light in vacuum= velocity of light in vacuum/ velocity of light in water=c/v
3×108m/s/2.25×108m/s
=1.33
Answered by BendingReality
3

Answer:

1.33

Explanation:

Given :

Speed of light in water = 2.25 × 10⁸ m / sec

We have

Speed of light in air = 3 × 10⁸ m / sec.

We know :

Refractive index = Speed of light in air / Speed of light in water

Putting value we get :

Refractive index = 3 × 10⁸ m / sec / 2.25 × 10⁸ m / sec

Refractive index = 1.33

Hence Refractive index is 1.33 .

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