the speed of light is in water is 2.25 × 10^8metre per second the speed of light is vacuum is 3 × 10^8 metre per second calculate refractive index of vacuum and water
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Answered by
51
refractive index = 3x10^8÷speed of light in denser medium
1)3 x10^8÷ 3x10^8=1
refractive index.of vaccum is 1
whereas,
2)3x10^8÷2.25x10^8=1.33...
refractive index of water is 1.3333.......
hope it helped u
1)3 x10^8÷ 3x10^8=1
refractive index.of vaccum is 1
whereas,
2)3x10^8÷2.25x10^8=1.33...
refractive index of water is 1.3333.......
hope it helped u
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Answered by
31
Heya!!
We know that reflective index in given by
u = speed of light in vacuum / speed of lights in medium
Now speed of light in water = 2.25×10^8 m/s
and in vacuum is 3×10^8m/s
Thus u(water) = 3×10^8/2.25×10^8
= 300/225 = 1.333...
Now u(vacuum) = 3×10^8/3×10^8
= 1
We know that reflective index in given by
u = speed of light in vacuum / speed of lights in medium
Now speed of light in water = 2.25×10^8 m/s
and in vacuum is 3×10^8m/s
Thus u(water) = 3×10^8/2.25×10^8
= 300/225 = 1.333...
Now u(vacuum) = 3×10^8/3×10^8
= 1
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