the speed of motor decreases from 1200rpm to 600rpm in 20s the total number of rotations it mqke before coming to rest is
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u = 1200 rpm = 20 rev/s
v = 600 rpm = 10 rev/s
t = 20s
angular acceleration, a=(20-10)/20 = -0.5 rev/s^2
u = 20 rev/s
v = 0
a = -0.5 rev/s^2
s = (v^2 - u^2)/2a = -20^2 / -(2×0.5) = 400 rev
Total number of rotation before stopping is 400.
v = 600 rpm = 10 rev/s
t = 20s
angular acceleration, a=(20-10)/20 = -0.5 rev/s^2
u = 20 rev/s
v = 0
a = -0.5 rev/s^2
s = (v^2 - u^2)/2a = -20^2 / -(2×0.5) = 400 rev
Total number of rotation before stopping is 400.
Answered by
0
Answer:u = 1200 rpm = 20 rev/s
v = 600 rpm = 10 rev/s
t = 20s
angular acceleration, a=(20-10)/20 = -0.5 rev/s^2
u = 20 rev/s
v = 0
a = -0.5 rev/s^2
s = (v^2 - u^2)/2a = -20^2 / -(2×0.5) = 400 rev
Total number of rotation before stopping is 400.
Explanation:
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