Question

The speed of sound in air at 0°C is 332 m/s.
If it increases at the rate of 0.6 m/s per degree,
what will be the temperature when the velocity
has increased to 344 m/s?​

Answer 1

Answer:

The speed of sound in air at 0℃ = 332m/s

Now, If it increases at the rate of 0.6m/s per degree,

Then, Speed at x℃ = (332 + 0.6x)℃

Thus, 344 = 332 + 0.6x

⇒ 344 - 332 = 0.6x

⇒ 12 = 0.6x

∴ x = \frac{12}{0.6}

= 20℃

Answer 2

$\huge \bigstar$$\huge\bold{\mathtt{\purple{✍︎A{\pink{N{\green{S{\blue{W{\red{E{\orange{R✍︎}}}}}}}}}}}}}$$\huge \Rightarrow$

$\Large \bold \red{Solution:}\Rightarrow$

In this case, $\upsilon$ at $t°$C =

$\large \upsilon$ at 0 °C + 0.6 t [in m/s]

Hence, by the data,

344 = 332 + 0.6 $t$

$\Rightarrow \Large t = \frac {344-332}{0.6}$

$\Rightarrow°C=\Large\frac {12}{0.6}$

$\Rightarrow$ °C = 20 °C

$\Large \bold \purple {Ans:}$

20°