Question

The speed of the car changes from 30 m/s to 20 m/s in five seconds calculate the acceleration produced and distance travelled by the car in this five seconds

Answer 1

Answer:

a=-10/5=-2m/s^2

s=30×5-(1/2)(-2)5^2

=150+25

=175m

Answer 2

$\huge\underline\orange{\mathcal Answer}$

$\large\blue{\boxed{\mathcal Acceleration (a) = -2m/s2}}$

$\large\blue{\boxed{\mathcal Distance (s) = 125 m }}$

$\huge\underline\orange{\mathcal Solution}$

Given :-

Initial Velocity (u) = 30 m/s

Final Velocity (v) = 20m/s

Acceleration (a) = ?

Distance (s) = ?

To find Acceleration (a) We know that :-

$\large{\boxed{\mathcal v = u + at}}$

$\large{\mathcal 20 = 30 + a×5}$

$\large{\mathcal 20-30 = 5a}$

$\large{\mathcal a ={\frac{-10}{5}}}$

$\huge{\boxed{\mathcal a = -2m/s2}}$

To find distance (s) We know that :-

$\large{\boxed{\mathcal s = ut+{\frac{1}{2}}a{t}^{2}}}$

$\large{\mathcal s = 30 × 5 + {\frac{1}{2}}(-2){5}^{2}}$

$\large{\mathcal s = 150 - 25}$

$\huge{\boxed{\mathcal s = 125m}}$

$\huge\orange{\mathcal Hope\:It\:Helps!!!}$