The speed of the car is 20m/s to travel a distance 40m. Then find the time taken by car.
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Answer:
160m
Explanation:
Initial velocity of car,u=20m/s
The final velocity will be,v=0 as the car comes to rest after travelling distance of 40m(which will be after application of breaks).
By third equation of motion we know,
v^2=u^2+2as
0 = (20)^2+2*a*40
- 80a=400
Thus,a= -5m/s^2
Negative signs indicates that it is a retardation.
When same car is moving with double the velocity.
Initial velocity,u=2*20=40m/s.
Thus,
0 = 40^2*2*(-5)*s
10s = 1600
s = 160m
Hence,if the same car is travelling at double the velocity the distance travelled by it for same retardation is 160 m.
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