Question

the speed of the electron in the first Bohr orbit ( in H atom ) of radius 0.53 A is 2200 km/s . calculate the frequency of revolution of the electron of the electron in the same orbit.​

Answer 1

Answar:If the velocity of the electron in the first Bohr orbit having radius 0.53 Å is 2200 km/s . What is the frequency of the electron in the same orbit ?

Answer 2

Given:

• The speed of the electron in the first Bohr orbit ( in H atom ) of radius 0.53 A is 2200 km/s .

To calculate:

• The frequency of revolution of the electron of the electron in the same orbit.

Solution:

We need to find frequency,

We know that,

♦ v = rω. ...1

Where,

v = velocity

r = radius

ω = Angular velocity

♦ ω = 2πF

Where,

F = Frequency

Substituting the value of ω in eq1, we have:

• v = r × 2πF

As we need to calculate the frequency of revolution of the electron of the electron in the same orbit, so

• F = v/2πr

Putting the values,

• F = (2200 × 10³)/(2 × π × 0.53 × 10⁻¹⁰)
• F = (1100 × 10³)/(π × 0.53 × 10⁻¹⁰)
• F = (1100 × 10³⁺¹⁰)/(π × 0.53)
• F = (1100 × 10¹³)/(3.14 × 0.53)
• F = 660.97 × 10¹³ Hz
• F = 6.6097 × 10¹⁵ Hz

Therefore, The frequency of revolution of the electron of the electron in the same orbit = 6.6097 × 10¹⁵ Hz

━━━━━━━━━━━━━━━━━━━━━