Question

the speed of train reduced from 180 kmph to 36 kmph over a distance of 400m calculated retardation produced.

Answer 1

vivfs=90 km h⋅1000 m1 km⋅1 h602 s=25 m/s=36 km h⋅1000 m1 km⋅1 h602 s=10 m/s=xi+vit+12at2=xi+vit+12⋅vf−vit⋅t2=0+25⋅5+12⋅10−255⋅52=87.5 mvi=90 km h⋅1000 m1 km⋅1 h602 s=25 m/svf=36 km h⋅1000 m1 km⋅1 h602 s=10 m/ss=xi+vit+12at2=xi+vit+12⋅vf−vit⋅t2=0+25⋅5+12⋅10−255⋅52=87.5 m