The spring has a force constant of 24N/m. The mass of the block attached to the spring is 4 kg. Initially the block is at rest and spring is unstretched. The horizontal surface is frictionless. If a constant horizontal force of 10N is applied on the block, then what is the speed of the block when it has been moved through a distance of 0.5 m?
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Answer:
Given
- spring force = 24N/M
- Mass of blocks = 4kg
- force applied = 10 N
To find
- speed of blocks when it is at 0.5 cm
Solution
the equations of motion is given as
F - KX = MA
10 - 24 × 5 = 4 × a
a = 27.5 m/s²
the speed is given as,
V² = U² + 2 ax
V² = (0)² + 2 × 27.5 × 0.5
V= 27.5 m/s
thus the speed of the block is 27.5 m/s.
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