Question

the square if the hypotenuse of an isosceles right angled triangle is 72 sq. cm.What is the length of each side

Answer 1

ac^2=ab^2+bc^2
72=ab^2+ab^2(ab=BC)
72=2ab^2
ab=root72/2
ab=6sq.cm
this is Right, the fig.is wrong

Answer 2

The length of the each side as per the given is 50.90 cm.

Step-by-step explanation:

Given:

The square if the hypotenuse of an isosceles right angled triangle is 72 sq. cm. What is the length of each side

Solution:

$AC^2 = AB^2 + BC^2$

From the given,

AC = 72, AB = BC

$72^2 = AB^2 + AB^2$

$72^2 = 2AB^2\\AB^2 = \frac{72^2}{2}\\AB = \sqrt{2592}$

= 50.9 cm

To know more:

The length of each side of an equilateral triangle of area 18 root 3cm sq

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