The taxi fare in a city follows for the first kilometre the fair is rupees 8 and for the subsequent distance is rupees 5 per kilometre taking the distance covered as x kilometre and Total fare rupees y write a linear equation for this information
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Answered by
6
simple see how ,
fare for 1 km is 8re
and other is 5reperkm
distance travel is x
then cost after 1km is 5(x-1)
equation is then
5+5(x-1)=y
5+5x-5=y
5x=y
fare for 1 km is 8re
and other is 5reperkm
distance travel is x
then cost after 1km is 5(x-1)
equation is then
5+5(x-1)=y
5+5x-5=y
5x=y
aruniqwerty:
sorry 8+5x-5
Answered by
2
8+5(x-1)=y x is the distance traveled in this we have traveled 1 km in rs 8 so 8 is constan we put 8 the further we travel cost rs 5. x is the further distance traveled multipliyed by rs 5 we minus 1 as rs 8 is added already which is the cost of 1 km and we get the equation 8+5into
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