the sum of the ages of father and his sons is 60 years. After 14 years, father's age will be three times the age of a son.find the present ages.
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Let the present age of father and son be X and Y.
A/Q,
X+Y = 60
X = 60-Y. ........(1)
AFTER 14 YEARS AGE OF FATHER = X+14
AFTER 14 YEARS AGE OF SON = Y+14
A/Q,
X+14 = 3(Y+14)
X+14 = 3Y + 42
X-3Y = 42-14
X-3Y = 28
Putting the Value of X in,
X-3Y = 28
60-Y-3Y = 28
-4Y = 28-60
-4Y = -32
4Y = 32
Y = 32/4 = 8
HENCE,
THE AGE OF SON = 8
AND,
THE AGE OF FATHER = 60-Y = 60-8 = 52 Years
A/Q,
X+Y = 60
X = 60-Y. ........(1)
AFTER 14 YEARS AGE OF FATHER = X+14
AFTER 14 YEARS AGE OF SON = Y+14
A/Q,
X+14 = 3(Y+14)
X+14 = 3Y + 42
X-3Y = 42-14
X-3Y = 28
Putting the Value of X in,
X-3Y = 28
60-Y-3Y = 28
-4Y = 28-60
-4Y = -32
4Y = 32
Y = 32/4 = 8
HENCE,
THE AGE OF SON = 8
AND,
THE AGE OF FATHER = 60-Y = 60-8 = 52 Years
Raven12:
it is sons. plural. not son.
sum of agea of sons and father is 60
not one son. there r more than one son
no of sons is not mentioned
its not there in the question
i think the question is wrong
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