the square of a natural number n is equal to 4 times the previous number. which one of the following equations correctly describes the situation?
a) n² - 4n - 4 = 0
b) n² + 4n + 4 = 0
c) n² + 4n - 4 = 0
d) n² - 4n + 4 = 0
Answers
Answered by
0
Let the natural number be 'n'.
So accordingly:
n² = 4(n-1)
n² = 4n - 4
or
n² - 4n + 4 = 0.
So the answer is option d.
So accordingly:
n² = 4(n-1)
n² = 4n - 4
or
n² - 4n + 4 = 0.
So the answer is option d.
Answered by
0
Solutions
Let the variable 'n' represent natural number .
Solve
n² = 4(n-1)
n² = 4n - 4
=
n² - 4n + 4 = 0.
The correct option would be (D)
Let the variable 'n' represent natural number .
Solve
n² = 4(n-1)
n² = 4n - 4
=
n² - 4n + 4 = 0.
The correct option would be (D)
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