The square of a number is 48 more than 22 times of itself. Find the number.
Answers
Answered by
1
Hey mate,
Let the number be x
then, according to the question,
x^2=22x+48
so,x^2-22x-48=0
by splitting middle term,
x^2+2x-24x-48=0
x(x+2)-24(x+2)=0
(x-24)(x+2)=0
x=24,or x=-2
This condition satisfies for both 24 and -2. So, both can be the required answer.
Hopes it is helpful
Answered by
0
X*X= 22x +48
X^2-22x-48
X^2-24x+2x-48
Solving quadratic equation by splitting the middle term
X=24/-2
X^2-22x-48
X^2-24x+2x-48
Solving quadratic equation by splitting the middle term
X=24/-2
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