The Square root of →
(3a+2b+3c)² - (2a+3b+2c)² + 5b² ?
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Answered by
2
√(3a+2b+3c)² - (2a+3b+2c)² + 5b²
= √9a² +4b²+ 9c² + 12ab+12bc+18ca - 4a² - 9b² -4c² -12ab-12bc-8ca + 5b²
= √5a²+ 5c²+10ca = √ (√5a+√5c)² = √5a+√5c
= √9a² +4b²+ 9c² + 12ab+12bc+18ca - 4a² - 9b² -4c² -12ab-12bc-8ca + 5b²
= √5a²+ 5c²+10ca = √ (√5a+√5c)² = √5a+√5c
Answered by
6
Hi friend!!!!
(3a+2b+3c)² - (2a+3b+2c)² + 5b²
9a²+4b²+9c²+12ab+12bc+18ac-(4a²+9b²+4c²+12ab+12bc+8ac)+5b²
=5a²-5b²+5c²+10ac+5b²
=5a²+5c²+10ac
=5(a²+c²+2ac)
square root of above expression will be
=√(5(a+c)²)
=√5*(a+c)
I hope this will help u ;)
(3a+2b+3c)² - (2a+3b+2c)² + 5b²
9a²+4b²+9c²+12ab+12bc+18ac-(4a²+9b²+4c²+12ab+12bc+8ac)+5b²
=5a²-5b²+5c²+10ac+5b²
=5a²+5c²+10ac
=5(a²+c²+2ac)
square root of above expression will be
=√(5(a+c)²)
=√5*(a+c)
I hope this will help u ;)
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