Math, asked by vivansa1455, 1 month ago

The square root of 4x2+20x+25 is

Answers

Answered by MrMonarque
10

Hello, Buddy!!

||Required Solution||

 \sqrt{(4 {x}^{2} + 20x + 25) }  \\  \sqrt{(4 {x}^{2}  + 10x + 10x + 25)}  \\  \sqrt{2x(2x + 5) +5(2x + 5) }  \\  \sqrt{(2x + 5)(2x + 5)}  \\  \sqrt{ {(2x + 5)}^{2} }  \\ 2x + 5 = 0 \\ 2x =  - 5 \\ x =  \frac{ - 5}{2}

  • Value of x ☞ -5/2

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