Question

The squared of five consecutive natural numbers add up to 3655. Find those numbers plse help I'll mark as BRAINLIEST show step by step​

Answer 1

Answer:

1st no. = 729

2nd no. = 729+ 1=730

3rd no. = 729 + 2 =731

4th no. = 729 + 3=732

5th no. = 729+ 4=733

Step-by-step explanation:

Let 1st number = x

2nd number = (x+1 )

3rd number = (x+2)

4th number = ( x+3)

5th number =(x+4)

x + x + 1 + x + 2 + x + 3 + x +4

5x + 10 = 3655

5x = 3655 - 10

5x = 3645

x =3645 /5

x = 729

Answer 2

Answer:

x+1+x+2+x+3+x+4+x+5=3655

5x+15=3655

5x=3655-15

5x=3640

x=3640

5

x=726

x+1=727

x+2=728

x+3=729

x+4=730

x+5=731

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