Question

the squares of two consecutive integers differ by 23 then the smallest integer is 11 how​

Answer 1

Answer:

The two integers are 11 and 12

Step-by-step explanation:

Here,

Let the consecutive integers be x and (x+1)

So, By the problem,

(x+1)²-x²=23

x²+2x+1-x²=23

2x+1=23

2x=22

x=22/2=11[PROVED]

So the two integers are 11 and 12

Answer 2

Pls mark as brainliest answer