The squre of greater of two consecutive even number exceed the squre of snaller by 36 find the number
Answers
Answered by
1
Answer:
Let us take the smaller number as X and
Greater number as X+2
According to the question,
(Greater no)^2 = (smaller no)^2+ 36
That is,
( X+2)^2 = x^2+ 36
= X^2 + 4X +4 = x^2+36
=4x +4 =36. ( X^2 canceled from
both the sides)
= 4x=36-4
= 4x=32
= X=32/4
= X= 8
So, the smaller number is X=8
And the greater number is X+2=8+2
=10
Hope this helped you ^_^
Similar questions