Question

The standard Gibbs energy for the given cell reaction in kJ mol⁻¹ at 298 K is:
Zn(s) + Cu²⁺ (aq) ———→ Zn²⁺ (aq) + Cu(s), Eᵒ = 2 V at 298K [Faraday’s constant F = 96500 C mol⁻¹] (A) -192 (B) 384
(C) -384 (D) 192

Answer 1

Explanation:

The standard Gibbs energy for the given cell reaction in kJ mol⁻¹ at 298 K is:

The standard Gibbs energy for the given cell reaction in kJ mol⁻¹ at 298 K is:Zn(s) + Cu²⁺ (aq) ———→ Zn²⁺ (aq) + Cu(s), Eᵒ = 2 V at 298K [Faraday’s constant F = 96500 C mol⁻¹] (A) -192 (B) 384

The standard Gibbs energy for the given cell reaction in kJ mol⁻¹ at 298 K is:Zn(s) + Cu²⁺ (aq) ———→ Zn²⁺ (aq) + Cu(s), Eᵒ = 2 V at 298K [Faraday’s constant F = 96500 C mol⁻¹] (A) -192 (B) 384(C) -384✓

(D) 192

Answer 2

$\huge\bold{Answer}$

-384