Question

The steam point and the ice point of a mercury thermometer are marked as 90o and 10o.What will be the temperature in centigrade mercury scale when this thermometer reads 30o

Answer 1

Let the reading of centigrade scale be C,

and that of mercury thermometer be M

total no. of divisions on centigrade scale = 100 - 0 = 100

total no. of divisions on mercury thermometer = 90 - 10 = 80

so, the realtionship between these two readings can be given by,

     $\frac{C}{100} = \frac{M - 10}{ 80}$

⇒ $C = 100 * \frac{30 - 10 }{80}$

⇒ C = 25°

∴the temperature in centigrade mercury scale is 25° c

HOPE THIS HELPS YOU !!

Answer 2

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The Relation is:

$\red\Rightarrow$$\huge\frac{Tc-10}{90-10}= \frac{Tc}{10}$

Tc is temperature in centigrate scale

T is the temperature measured by mercury thermometer and gives to be 30°

$\huge\red\Rightarrow \huge\frac{30-10}{90-10}= \frac{Tc}{100}$

$\huge\red\Rightarrow \huge\frac{20}{80}= \frac{Tc}{100}$

$\huge\red\Rightarrow \huge\frac{2}{8} = \frac{Tc}{100}$

$\huge\red\Rightarrow \huge\frac{1}{4} = \frac{Tc}{100}$

$\huge\red\Rightarrow 4.Tc =100$

$\huge\red\Rightarrow Tc = \frac{100}{4}$

$\huge\red\Rightarrow$$\huge{Tc= 25°}$

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