Question

The steel is 50cm long at 10 °C. The coefficient of linear expansion for steel is 12 × 10⁻⁶ °C. Calculate the increase in length and the final length when it is 70 °C.​

Answer 1

Explanation:

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Answer 2

Given :

The change in temperature (ΔT) = 70°C – 10°C = 60°C

The original length (L1) = 50 cm

Coefficient of linear expansion for steel (α) = 12 x 10^-6 (Co)

To find : The change in length (ΔL) and the final length (L2)

Solution :

a) The change in length (ΔL)

ΔL = α L1 ΔT

ΔL = (12×10^-6 °C-1)(50 cm)(60°C)

ΔL = (10^-6)(36 x 10^3) cm

ΔL = 36 x 10^-3 cm

ΔL = 36 / 10^3 cm

ΔL = 36 / 1000 cm

ΔL = 0.036 cm

b) The final length (L2)

L2 = L1 + ΔL

L2 = 50 cm + 0.036 cm

L2 = 50.036 cm

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