The straight line ax+by+c=0 where 3a+2b+4c=0 are concurrent the point
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Dear student
3a+2b+4c = 0
Dividing the equation by 4
3a/4+2b/4+4c/4 = 0
=> 3a/4 + b/2+c = 0
x = ¾ and y = ½ satisfied this relation
Hence the set of lines are concurrent at (3/4, ½)
3a+2b+4c = 0
Dividing the equation by 4
3a/4+2b/4+4c/4 = 0
=> 3a/4 + b/2+c = 0
x = ¾ and y = ½ satisfied this relation
Hence the set of lines are concurrent at (3/4, ½)
Answered by
1
Dear student
3a+2b+4c = 0
Dividing the equation by 4
3a/4+2b/4+4c/4 = 0
=> 3a/4 + b/2+c = 0
x = ¾ and y = ½ satisfied this relation
Hence the set of lines are concurrent at (3/4, ½)
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