Question

The sum of the two digits of a two digit number is 15 and the difference between the two digits of the number is 3. what is the product of the two digits of that number?

Answer 1

✫Solution✫

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✑ Let x and y be tenth and unit digit .

Required Number = xy

A/Q

Case 1 :- When sum of the digits is 15 ,where x>y

⇒ x+y =15 ___(1)

Case 2:- When difference between two digits is 3 , where x>y

⇒x-y =3 ____(2)

Adding both the equation we will get

⇒2x= 18

⇒x=18/2

⇒x=9

Putting x=9 in (1) we get

⇒9+y=15

⇒y= 15-9

⇒y= 6

✑ Thus product of two digits (xy)= 6×9= 54

⍟Alter method

When x<y

⇒y-x= 3 _____(3)

Adding (3) and (1) we get

⇒2y= 18

⇒y=18/2

⇒y=9

Putting y=9 in (1) we get x= 6

Thus ,

✑ Product of digits (xy) = 54

✎NOTE:- In question there isn't given which value Is greater so we can make it by two methods

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