The straight line drawn from the centre of a circle to bisect a chord is perpendicular to the chord.
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RAY OR DIAMETER IS THE STRAIGHT LINE DRAWN FROM THE CIRCLE TO BISECT A CHORD IS PERPENDICULAR TO THE CHORD
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The straight line OD bisect the chord AB of the circle with Centre O at the point D.
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OD ⊥ AB.
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OA and OB are joined.
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In ∆ OAD and OBD,
OA =OB (radii of the same circle)
AD = BD (D is the mid - point of the chord AB)
OD is common.
∴ ∆ are congruent (sss congruency)
∴ ∠ODA = ∠ODB but ∠ODA +∠ODB = 180°
∴ ∠ODA = ∠ODB = 90°
∴ OD ⊥AB (proved)
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