The straight line x+2y = 1 meets the
coordinate axes at A and B. A circle is
drawn through A,B and the origin. Then
the sum of perpendicular distances from
A and B on the tangent to the circle at the
origin is
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let us take out the point A and B
when ,the line intersect at y axis then it's abcissa will be zero...
put this in the given eqaution....
0-2y=1
Y=-1/2
hence coordinates of A is(0,-1/2)
no,when the same line interecft at y-axis then it's ordinate will be zero
put this in eqaution of line
x=1
hence coordinates of B is (1,0)
eqaution of circle will be
(x-1)(x-0))+(y-0)(y-1/2)=0
x^2+y^2-x-y/2=0
now,we know, eqaution of tangent,as x+2y=1
also
then sum=2/√5 +1/2√5
=(4+1)/2√5
=5/2√5
=√5/2
hope it helps you
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