Question

The street accident in a town decreases by 10 % in comparison to its previous year. In the present year, if the number of street accidents be 3645, find the number of street accidents in the town 3 years before.​

Answer 1

Answer:

1st year accidents = 364500

2nd year accidents = 36450

3rd year accidnts = 3645

Step-by-step explanation:

$\frac{10}{100} *x---------- 1st year\\\\\frac{10}{100}*(\frac{10}{100}x ) --------- 2nd year\\\\\frac{10}{100}[\frac{10}{100}(\frac{10}{100}x )] ---------3rd year$

$\frac{x}{10} -----1st year\\\\\frac{x}{100} ------ 2nd year\\\\\frac{x}{1000} ------ 3rd year</p><p></p><p>[tex]3645 = \frac{x}{1000} \\\\3645000 = x$

$\frac{3645000}{10} = 364500 ----- 1st year accidents \\\\\frac{3645000}{100} = 3650 ----- 2nd year accidents \\\\\frac{3645000}{1000} = 3645 ---- 3rd year accidents$