Question

The string of a kite is 150 m long and it makes an angle 60° with the horizontal. Find the height of the kite above the ground. (Assume string to be tight)

Answer 1

LINE OF SIGHT: The line of sight is a line drawn from the eye of an observer to the point in the object viewed by the observer.

ANGLE OF ELEVATION: The angle of elevation of an object viewed is the angle formed by the line of sight with the horizontal , when it is above the horizontal level.

ANGLE OF DEPRESSION:The angle of depression of an object viewed is the angle formed by the line of sight with the horizontal , when it is below the horizontal level.

•Angle of elevation and depression are always acute angles.

•If the observer moves towards the perpendicular line(Tower/ building) then angle of elevation increases and if the observer move away from the perpendicular line(Tower/ building) angle of elevation decreases.

SOLUTION:

GIVEN:
∠BAC = 60° (angle of elevation)
AC =  150 m be length of the String of the kite

Let BC = x m be the height of the kite above  the ground

In ∆ABC ,
sin 60° = BC / AC = P/ H
√3/2 = x / 150
2x  = 150√3
x = (150√3 / 2)
x= 75√3  m

AC = 75√3 m

Hence , the height of the kite above  the ground is 75√3 m.

HOPE THIS WILL HELP YOU...

Answer 2

answer is 75underroot 3 .... plz see the attachment