Question

The string of a violin a note of 400 H_(Z) at its correct tension . The string is bit taut and produces 5 beats per second with a tuning fork of frequency 400 H_(Z) . Find frequency of the note emitted by this taut string .

Answer 1

Frequency emitted by taut string is 405 Hz

Explanation:

Given :

Frequency of violin $f_{v} = 400$ Hz

Frequency of tuning fork $f_{t} = 400$ Hz

No. of beats = 5

From the formula of speed of waves in string,

   $v = \sqrt{\frac{T}{\mu} }$

Where $v =$ speed of wave,

And from above formula we can say that frequency of the wave is increase as tension increase     ( $v = f \lambda$ )

Thus new emitted frequency is grater than 400 Hz

 $f_{n} = 400 +5$

 $f_{n} = 405$ Hz