Question

The structure of IF7 is
A) Pentagonal bipyramid
B) Square pyramid
C) Trigonal bipyramid
D) Octahedral

Answer 1

we have,

Hybridization in IF7 is

$s {p}^{3} {d}^{3}$

Thus, by VSEPR theory ,it has Pentagonal bipyramidal structure.It has no lone pair of electron.So,no structure modifications

Thanks

KSHITIJ

Answer 2

$Here \: is \: the \: answer \: of \: your \: question$


$\huge\textbf{IF7}$


Valence number of electrons in I = 7

Atom of F = 7

Formula = ½ (V + M - C + A)

= ½ (7 + 7)

= ½ (14)

= 7


In above Formula;

V = Number of valence electrons in central atom.

M = Number of monocovalent atoms around the central atom.

C = Positive charge on cation.

A = Negative charge on anion.


So, It's Hyberdization is S¹p³d³.


According to VSPER theory (Valence Shell Electron Pair Theory). It's structure is $\textbf{Pentagonal bipyramid.}$ Also it has no lone pair in it.


Diagram is in Attachment!!


So, correct option is


$\huge\textbf{A) Pentagonal bipyramid...}$

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