the student saves Rs:1 on the second day, Rs:3 on the third day and so on. Then, during the month of April, he has saved Rs...
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a=1
d=1
n=1
Now,
Sn= n\2【2a+(n-1)d】
S30= 30\2【2×1(30-1)1
S30=15【2+29】
S30= 15× 31
S30= 495
Therefore he saving on the month of April is Rs.495
d=1
n=1
Now,
Sn= n\2【2a+(n-1)d】
S30= 30\2【2×1(30-1)1
S30=15【2+29】
S30= 15× 31
S30= 495
Therefore he saving on the month of April is Rs.495
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