The students of a class are made to stand in complete rows. If one student is extra in a row, there would be 2 rows less, and if one student is less in a row, there would be 3 rows more. Find the number of students in the class.
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Let the number of rows be x and number of students in a row be y.
Total number of students in the class
= Number of rows x Number of students in a row
= xy
According to the question,
Total number of students = (x - 2) (y + 1)
xy = (x - 2) (y + 1)
Total number of students = (x + 3) (y - 1)
xy = (x + 3) (y - 1)
Simplify the above two equations to find the values of x and y.
Total number of students in the class
= Number of rows x Number of students in a row
= xy
According to the question,
Total number of students = (x - 2) (y + 1)
xy = (x - 2) (y + 1)
Total number of students = (x + 3) (y - 1)
xy = (x + 3) (y - 1)
Simplify the above two equations to find the values of x and y.
Answered by
2
Answer:
60
Step-by-step explanation:
Let the number of students in one row be taken as x
And let the number of rows be taken as y
Then the total number of students = xy
Then according to the first condition given in the problem, we have
(x + 1) (y – 2) = xy
xy – 2x + y – 2 = xy
-2x + y = 2 … (i)
And, according to the second condition given in the problem, we have
(x – 1) (y + 3) = xy
xy + 3x – y – 3 = xy
3x – y = 3 … (ii)
Adding equations (i) and (ii), we get
-2x + y = 2
3x – y = 3
————–
x = 5
On substituting the value of x in equation (i), we have
-2(5) + y = 2
-10 + y = 2
y = 2 + 10
y = 12
Therefore, the number of students = xy = 5 x 12 = 60.
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