Question

The students while solving a quadratic equation in x, one copied the constant term incorrectly and got the roots 3 and 2. The other copied the constant term and coefficient of x^2 as -6 and 1 Respectively the correct roots are


with explanation please​

Answer 1

Answer:

2x+3y=12 xy=6

8x3+27y3

=(2x)3+(3y)3

=a3+b3=(a+b)(a2+b2−ab)

8x3+27y3=(2x+3y)((2x)2+(3y)2−(2x)(3y))

=(12)[(2+3y)2−12xy−6xy]

=(12)[(12)2−18(6)]

=12[144−108]

=12×36

=432.

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