The su of three consecutive integers is 20.what are the threeintegers?
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Answered by
2
Let,
The first integer be x
Then,
The second integer= x+1
The third integer= x+2
Now,
x+x+1+x+2= 20
3x+3= 20
x= (20-3)/3
x= 17/3
So,
First integer= x= 17/3
Second integer= x+1= 17/3+1= 20/3
Third integer= x+2= 17/3+2= 23/3
Hope this helps you!
The first integer be x
Then,
The second integer= x+1
The third integer= x+2
Now,
x+x+1+x+2= 20
3x+3= 20
x= (20-3)/3
x= 17/3
So,
First integer= x= 17/3
Second integer= x+1= 17/3+1= 20/3
Third integer= x+2= 17/3+2= 23/3
Hope this helps you!
akshatajay1410:
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Answered by
2
let the three integers be x,x+1,x+2
x+x+1+x+2=20
3x+3=20
3x=17
x=17/3
x+1=17/3+1=17+3/3=20/3
x+2=17/3+2=17+6/3=23/3
x+x+1+x+2=20
3x+3=20
3x=17
x=17/3
x+1=17/3+1=17+3/3=20/3
x+2=17/3+2=17+6/3=23/3
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