Math, asked by rshruthikaa6ozkhqs, 1 year ago

the sum a3/b-a and b3/a-b is

Answers

Answered by AR17
7
Heya user !!

Here's the answer you are looking for
  \frac{ {a}^{3} }{b - a}  +   \frac{ {b}^{3} }{a - b}   \\  \\ \frac{ -  {a}^{3} }{a - b}   +  \frac{ {b}^{3} }{a - b}  \\  \\  \frac{ {b}^{3}  -  {a}^{3} }{a - b}  \\  \\  \frac{(b - a)( {b}^{2}  + ab +  {a}^{2} )}{(a - b)}  \\  \\  \frac{ - (a - b)( {b}^{2}  + ab +  {a}^{2} )}{(a - b)}  \\  \\   - ({b}^{2}  + ab +  {a}^{2} ) \\


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