Question

the sum and product of the zeros of the polynomial x cube - 7 x - 12 are

Answer 1

Answer:

Let f(x) = x2 + 7x + 12 f(x) = x2 + 4x + 3x + 12 f(x) = x(x+4) + 3(x+4) f(x) = (x+4)(x+3) To find the zeroes, set f(x) = 0, then either (x + 4) = 0 or (x + 3) = 0 x = −4 or x = −3 Again, Sum of zeroes = (-4 – 3) = -7 = -7/1 = -b/a = (-Coefficient of x)/(Cofficient of x^2) Product of zeroes = 12 = 12/1 = c/a = Constant term / Coefficient of x^2

Answer 2

Answer:

Given polynomial x²+7x+12x²+4x+3x +12x(x+4)+3(x+4)(x+3)(x+4)-3,-4 are the zerossum of zeros=-7=-b/a=-7product of zeros =12=c/a=12hence ...

Step-by-step explanation:

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